std::is_sorted

Defined in header `<algorithm>`
	(1)
template< class ForwardIt > bool is_sorted( ForwardIt first, ForwardIt last );			(since C++11) (until C++20)
template< class ForwardIt > constexpr bool is_sorted( ForwardIt first, ForwardIt last );			(since C++20)
template< class ExecutionPolicy, class ForwardIt > bool is_sorted( ExecutionPolicy&& policy, ForwardIt first, ForwardIt last );		(2)	(since C++17)
		(3)
template< class ForwardIt, class Compare > bool is_sorted( ForwardIt first, ForwardIt last, Compare comp );				(since C++11) (until C++20)
template< class ForwardIt, class Compare > constexpr bool is_sorted( ForwardIt first, ForwardIt last, Compare comp );				(since C++20)
template< class ExecutionPolicy, class ForwardIt, class Compare > bool is_sorted( ExecutionPolicy&& policy, ForwardIt first, ForwardIt last, Compare comp );			(4)	(since C++17)

Checks if the elements in range [first, last) are sorted in non-descending order.

1) Elements are compared using operator<.

3) Elements are compared using the given binary comparison function comp.

2,4) Same as (1,3), but executed according to policy. These overloads do not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true

Parameters

first, last	-	the range of elements to examine
policy	-	the execution policy to use. See execution policy for details.
comp	-	comparison function object (i.e. an object that satisfies the requirements of Compare) which returns true if the first argument is less than (i.e. is ordered before) the second. The signature of the comparison function should be equivalent to the following: bool cmp(const Type1 &a, const Type2 &b); While the signature does not need to have const &, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) `Type1` and `Type2` regardless of value category (thus, Type1 & is not allowed, nor is Type1 unless for `Type1` a move is equivalent to a copy (since C++11)). The types Type1 and Type2 must be such that an object of type ForwardIt can be dereferenced and then implicitly converted to both of them.
Type requirements
- `ForwardIt` must meet the requirements of LegacyForwardIterator.

Return value

true if the elements in the range are sorted in ascending order

Complexity

linear in the distance between first and last

Exceptions

The overloads with a template parameter named ExecutionPolicy report errors as follows:

If execution of a function invoked as part of the algorithm throws an exception and ExecutionPolicy is one of the standard policies, std::terminate is called. For any other ExecutionPolicy, the behavior is implementation-defined.
If the algorithm fails to allocate memory, std::bad_alloc is thrown.

Possible implementation

First version

template<class ForwardIt>
bool is_sorted(ForwardIt first, ForwardIt last)
{
    return std::is_sorted_until(first, last) == last;
}

Second version

template<class ForwardIt, class Compare>
bool is_sorted(ForwardIt first, ForwardIt last, Compare comp)
{
    return std::is_sorted_until(first, last, comp) == last;
}

Notes

std::is_sorted and std::is_sorted_until both return true for empty ranges and ranges of length one.

Example

Run this code

#include <iostream>
#include <algorithm>
#include <iterator>
int main() 
{
    int digits[] = {3, 1, 4, 1, 5};
 
    for (auto i : digits) std::cout << i << ' ';
    std::cout << ": is_sorted: " << std::boolalpha
              << std::is_sorted(std::begin(digits), std::end(digits)) << '\n';
 
    std::sort(std::begin(digits), std::end(digits));
 
    for (auto i : digits) std::cout << i << ' ';
    std::cout << ": is_sorted: "
              << std::is_sorted(std::begin(digits), std::end(digits)) << '\n';
}

Output:

3 1 4 1 5 : is_sorted: false
1 1 3 4 5 : is_sorted: true

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